x^2-16x-560=0

Solution for x^2-16x-560=0 equation:

x^2-16x-560=0

a = 1; b = -16; c = -560;
Δ = b2-4ac
Δ = -162-4·1·(-560)
Δ = 2496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2496}=\sqrt{64*39}=\sqrt{64}*\sqrt{39}=8\sqrt{39}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-8\sqrt{39}}{2*1}=\frac{16-8\sqrt{39}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+8\sqrt{39}}{2*1}=\frac{16+8\sqrt{39}}{2}
$